第二次作业

01-homework-daxiong.py

+# 石头与宝石
+Jewels = input("请输入宝石的类型\n")
+Stones = input("请输入具有的石头为\n")
+count = 0
+
+for i in range(len(Jewels)):
+    for j in range(len(Stones)):
+        if Jewels[i] == Stones[j]:
+            count += 1
+print("\n")
+str = '%d' % count  # 将数字转化成字符串
+print('石头中具有的宝石数目为' + str)  # 如何换行后再输出count
+
+print('---------------')
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