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1-homework-yanjun
Commit 23ca2b7d by bonnieyan
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部分提交作业

parent ffa74899
Showing with 421 additions and 0 deletions
14-homework-yanjun/.ipynb_checkpoints/pymysql_crud_homework-checkpoint.ipynb 0 → 100644
{
"cells": [
{
"cell_type": "code",
"execution_count": 2,
"metadata": {},
"outputs": [],
"source": [
" # TODO：连接数据库\n",
"import pymysql\n",
"import pandas as pd\n",
"import matplotlib.pyplot as plt\n",
"# 打开数据库连接\n",
"db = pymysql.connect(host='localhost',\n",
" user='root',\n",
" password='root',\n",
" db='test_db',\n",
" charset='utf8mb4',\n",
" cursorclass=pymysql.cursors.DictCursor)"
]
},
{
"cell_type": "code",
"execution_count": 20,
"metadata": {},
"outputs": [
{
"data": {
"text/html": [
"<div>\n",
"<style scoped>\n",
" .dataframe tbody tr th:only-of-type {\n",
" vertical-align: middle;\n",
" }\n",
"\n",
" .dataframe tbody tr th {\n",
" vertical-align: top;\n",
" }\n",
"\n",
" .dataframe thead th {\n",
" text-align: right;\n",
" }\n",
"</style>\n",
"<table border=\"1\" class=\"dataframe\">\n",
" <thead>\n",
" <tr style=\"text-align: right;\">\n",
" <th></th>\n",
" <th>applicant</th>\n",
" <th>status</th>\n",
" </tr>\n",
" </thead>\n",
" <tbody>\n",
" <tr>\n",
" <th>0</th>\n",
" <td>20000001</td>\n",
" <td>REPAID</td>\n",
" </tr>\n",
" <tr>\n",
" <th>1</th>\n",
" <td>20000001</td>\n",
" <td>REPAID</td>\n",
" </tr>\n",
" <tr>\n",
" <th>2</th>\n",
" <td>20000001</td>\n",
" <td>REPAID</td>\n",
" </tr>\n",
" <tr>\n",
" <th>3</th>\n",
" <td>20000002</td>\n",
" <td>RETURNING</td>\n",
" </tr>\n",
" <tr>\n",
" <th>4</th>\n",
" <td>20000002</td>\n",
" <td>IN_PROGREESS</td>\n",
" </tr>\n",
" <tr>\n",
" <th>5</th>\n",
" <td>20000002</td>\n",
" <td>REPAID</td>\n",
" </tr>\n",
" <tr>\n",
" <th>6</th>\n",
" <td>20000003</td>\n",
" <td>REPAID</td>\n",
" </tr>\n",
" <tr>\n",
" <th>7</th>\n",
" <td>20000003</td>\n",
" <td>IN_PROGREESS</td>\n",
" </tr>\n",
" <tr>\n",
" <th>8</th>\n",
" <td>20000004</td>\n",
" <td>IN_PROGREESS</td>\n",
" </tr>\n",
" <tr>\n",
" <th>9</th>\n",
" <td>20000004</td>\n",
" <td>REPAID</td>\n",
" </tr>\n",
" </tbody>\n",
"</table>\n",
"</div>"
],
"text/plain": [
" applicant status\n",
"0 20000001 REPAID\n",
"1 20000001 REPAID\n",
"2 20000001 REPAID\n",
"3 20000002 RETURNING\n",
"4 20000002 IN_PROGREESS\n",
"5 20000002 REPAID\n",
"6 20000003 REPAID\n",
"7 20000003 IN_PROGREESS\n",
"8 20000004 IN_PROGREESS\n",
"9 20000004 REPAID"
]
},
"execution_count": 20,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"# # 查询person表\n",
"# person_sql =\n",
"# person_detail=pd.read_sql(sql=person_sql,con=db)\n",
"\n",
"# 查询apply表\n",
"apply_sql = 'select applicant, status from apply limit 10'\n",
"apply_detail = pd.read_sql(sql=apply_sql, con=db)\n",
"apply_detail\n",
"\n",
"\n",
"\n",
"# # 查询call表\n",
"# call_sql =\n",
"# call_detail=pd.read_sql(sql=call_sql,con=db)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
" ## 任务1：查询某个用户是否有处于OVERDUE状态的进件\n",
" 方法1: 通过代码查询 <br> 方法2: 通过sql语句查询"
]
},
{
"cell_type": "code",
"execution_count": 21,
"metadata": {},
"outputs": [
{
"ename": "IndentationError",
"evalue": "unexpected indent (<ipython-input-21-fe8ee5f1b5a0>, line 6)",
"output_type": "error",
"traceback": [
"\u001b[0;36m File \u001b[0;32m\"<ipython-input-21-fe8ee5f1b5a0>\"\u001b[0;36m, line \u001b[0;32m6\u001b[0m\n\u001b[0;31m for p in apply_list：\u001b[0m\n\u001b[0m ^\u001b[0m\n\u001b[0;31mIndentationError\u001b[0m\u001b[0;31m:\u001b[0m unexpected indent\n"
]
}
],
"source": [
"# 获取当前借款人是否有OVERDUE状态的进件（通过代码实现）\n",
"def get_od_apply(person_id):\n",
" # 通过apply_detail拿到'applicant','status'两列的值\n",
" \n",
" apply_list = apply_detail\n",
" for p in apply_list：\n",
" if p == persion_id:\n",
" print(app_list[p])\n",
" # 遍历apply_list,找到person_id，如果有OVERDUE状态进件则返回True，否则返回False\n",
"\n",
"print(get_od_apply(20000001)) # False\n",
"# print(get_od_apply(20000035)) # True"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": []
}
],
"metadata": {
"kernelspec": {
"display_name": "Python 3",
"language": "python",
"name": "python3"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
"version": 3
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.6.5"
}
},
"nbformat": 4,
"nbformat_minor": 2
}
14-homework-yanjun/operate_mysql.py 0 → 100644
# TODO：连接数据库
import pymysql
import pandas as pd
import matplotlib.pyplot as plt
# 打开数据库连接
db = pymysql.connect(host='localhost',
user='root',
password='root',
db='test_db',
charset='utf8mb4',
cursorclass=pymysql.cursors.DictCursor)
# 查询apply表
apply_sql = 'select applicant, status from apply'
apply_detail = pd.read_sql(sql=apply_sql, con=db)
def get_od_apply(person_id):
# 通过apply_detail拿到'applicant','status'两列的值
#将dataFrame转换为numpy.ndarray
apply_list_1 = apply_detail.values
# print(type(apply_list_1))
#将numpy.ndarrayz转换为list
apply_list = apply_list_1.tolist()
# print(apply_list)
for i in apply_list:
# print(i)
# print(i[0])
# print(i[1])
# print(type(i[1]))
if i[0] == person_id:
if i[1] == 'OVERDUE':
return True
else:
continue
if i[0] > person_id:
return False
# print(apply_list)
# print(type(apply_list))
# for p in apply_list:
# print(p)
# if p == person_id:
# print(p)
# return p
# 遍历apply_list,找到person_id，如果有OVERDUE状态进件则返回True，否则返回False
# print(get_od_apply(20000004))
if __name__ =="__main__":
print(get_od_apply(20000004))
print(get_od_apply(20000035))
14-homework-yanjun/pymysql_crud_homework.ipynb 0 → 100644
{
"cells": [
{
"cell_type": "code",
"execution_count": 20,
"metadata": {},
"outputs": [],
"source": [
" # TODO：连接数据库\n",
"import pymysql\n",
"import pandas as pd\n",
"import matplotlib.pyplot as plt\n",
"# 打开数据库连接\n",
"db = pymysql.connect(host='localhost',\n",
" user='root',\n",
" password='root',\n",
" db='test_db',\n",
" charset='utf8mb4',\n",
" cursorclass=pymysql.cursors.DictCursor)"
]
},
{
"cell_type": "code",
"execution_count": 23,
"metadata": {},
"outputs": [
{
"ename": "SyntaxError",
"evalue": "invalid syntax (<ipython-input-23-51515430e9dc>, line 2)",
"traceback": [
"\u001b[0;36m File \u001b[0;32m\"<ipython-input-23-51515430e9dc>\"\u001b[0;36m, line \u001b[0;32m2\u001b[0m\n\u001b[0;31m person_sql ='(select count(MALE) from person where sex = 'MALE' union all select count(FEMALE) from person where sex = 'FEMALEMALE')'\u001b[0m\n\u001b[0m ^\u001b[0m\n\u001b[0;31mSyntaxError\u001b[0m\u001b[0;31m:\u001b[0m invalid syntax\n"
],
"output_type": "error"
}
],
"source": [
"# # 查询person表\n",
"person_sql ='(select count(MALE) from person where sex = 'MALE' union all select count(FEMALE) from person where sex = 'FEMALEMALE')'\n",
"person_detail=pd.read_sql(sql=person_sql,con=db)\n",
"\n",
"# 查询apply表\n",
"# apply_sql = 'select applicant, status from apply'\n",
"# apply_detail = pd.read_sql(sql=apply_sql, con=db)\n",
"\n",
"\n",
"\n",
"# # 查询call表\n",
"# call_sql =\n",
"# call_detail=pd.read_sql(sql=call_sql,con=db)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
" ## 任务1：查询某个用户是否有处于OVERDUE状态的进件\n",
" 方法1: 通过代码查询 <br> 方法2: 通过sql语句查询"
]
},
{
"cell_type": "code",
"execution_count": 6,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"False\n",
"True\n"
]
}
],
"source": [
"# 获取当前借款人是否有OVERDUE状态的进件（通过代码实现）\n",
"def get_od_apply(person_id):\n",
" # 通过apply_detail拿到'applicant','status'两列的值\n",
" apply_list_1 = apply_detail.values\n",
" apply_list = apply_list_1.tolist()\n",
" # 遍历apply_list,找到person_id，如果有OVERDUE状态进件则返回True，否则返回False\n",
" for i in apply_list:\n",
" if i[0] == person_id:\n",
" if i[1] == 'OVERDUE':\n",
" return True\n",
" else:\n",
" continue\n",
" if i[0] > person_id:\n",
" return False\n",
" \n",
"print(get_od_apply(20000001)) # False\n",
"print(get_od_apply(20000035)) # True"
]
},
{
"cell_type": "code",
"execution_count": 22,
"metadata": {},
"outputs": [],
"source": [
"# TODU：获取当前借款人是否有OVERDUE状态的进件（通过sql语句实现）\n",
"\n",
"# sql查询用户id为20000035的用户是否有OVERDUE状态的进件\n",
"#sql1 = select applicant,status from apply where applicant =20000035 and status = 'OVERDUE' \n",
"# status1 = \n",
"# print(stauts1) \n",
"\n",
"\n",
"# # sql查询用户id为20000001的用户是否有OVERDUE状态的进件\n",
"# sql2 = select applicant,status from apply where applicant =20000001 and status = 'OVERDUE'\n",
"# stauts2 = \n",
"# print(stauts2) # 0"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### 任务2：\n",
"1.根据给定金融借款数据，分析出在已知借款人中，男女的具体比例。根据查询结果，画出饼图进行展示。<br>\n",
"2.查询各种状态进件所占百分比，画出饼图进行展示。<br>\n",
"3.根据进件状态，分析出男人逾期的概率大还是女人逾期的概率大。<br>\n",
"\n"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# TODU:查询男、女各占比例,并绘制成饼图\n",
"# 从person_info中获取'FEMALE','MALE'的人数\n",
"value = \n",
"# 绘制饼图\n",
"plt.pie()\n",
"plt.show()"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Python 3",
"language": "python",
"name": "python3"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
"version": 3
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.6.5"
}
},
"nbformat": 4,
"nbformat_minor": 2
}
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